9(6d+3d^2)=+4d

Solution for 9(6d+3d^2)=+4d equation:

9(6d+3d^2)=+4d

We move all terms to the left:

9(6d+3d^2)-(+4d)=0

We multiply parentheses

27d^2+54d-(+4d)=0

We get rid of parentheses

27d^2+54d-4d=0

We add all the numbers together, and all the variables

27d^2+50d=0

a = 27; b = 50; c = 0;
Δ = b2-4ac
Δ = 502-4·27·0
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2500}=50$
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(50)-50}{2*27}=\frac{-100}{54}
=-1+23/27
$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(50)+50}{2*27}=\frac{0}{54}
=0
$